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教了节四年级的数学课。课后,心情久久不能平静,学生积极、灵动的思维启迪了我,感染了我。课上,我出示一个实际问题:甲、乙两地相距200千米,汽车行完全程要5小时,步行要40小时。张强从甲地出发,先步行8小时后改乘汽车,还需要几小时到达到乙地?对于四年级学生来说,这道题并不难,所以,同学们很快就解决了这个问题:先求汽车的速度(200÷5=)40(千米);再求步行的速度(200÷40=)5(千米),先步行8小时就是(5×8=)40(千米);全程200千米,乘汽车行了(200-40=)160(千米),所以,还需要(160÷40=)4(小时)到达乙地。
Teach the fourth grade math class. After class, the mood can not be calm for a long time. The students’ positive and clever thinking inspired me and infected me. During class, I showed you a practical question: A and B are 200 kilometers apart. The car journey takes 5 hours and the walk to 40 hours. Zhang Qiang starting from a, 8 hours after the first change to the car, but also take a few hours to reach B? For the fourth grade students, this problem is not difficult, so students quickly solved the problem: First seek the speed of the car (200 ÷ 5 =) 40 (km); and then seek the speed of walking (200 ÷ 40 =) 5 (km), first eight hours is (5 × 8 = ; Full 200 km, by car (200-40 =) 160 (km), so, also need (160 ÷ 40 =) 4 (hours) to reach B.