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在教学中,对于一些典型的习题,引导学生从不同的角度,用不同的方法去分析,可以使学生在分析和练习过程中加深对基本概念和基本理论的理解,从而更牢靠地记忆和掌握所学基础知识。现举一溶液计算的化学例题来说明。例:30℃时,硫酸铜饱和水溶液的浓度为20%,取250克此溶液,从中蒸发出50克水分,问当蒸发水分后的溶液温度降低到30℃时能析出 CuSO_4·5H_2O 晶体多少克?总分析:本题按题意可用图形表示如下:
In teaching, for some typical exercises, to guide students from different angles, using different methods to analyze, can make students in the process of analysis and practice to deepen the understanding of basic concepts and basic theory, so as to more firmly remember and master Learn the basics. Now give a chemical solution to calculate the solution to illustrate. Example: 30 ℃, the concentration of saturated aqueous solution of copper sulfate was 20%, take 250 grams of this solution, evaporate 50 grams of water, asked when the evaporation of water after the solution temperature dropped to 30 ℃ can precipitate CuSO_4 · 5H_2O crystal grams ? Total Analysis: This question can be used by the graphical representation as follows: