物体在某一平衡位置附近做往复运动称为振动,求解振动特别是简谐运动的周期是物理竞赛中的一个重要内容,也是学生感到比较困难的地方,本文试对此作一归纳总结.一、公式法如果物体做的是简谐运动,则其所受的回复力 F与相对于平衡位置的位移 x 满足如下关系,即F=-kx.理论上可以证明,这个运动微分方程的解为x=Acos(ωt+φ0),ω是振动物体的圆频率,它由系统本身的性质决定,即 The reciprocating motion of an object near a certain equilibrium position is called vibration. Solving the cycle of vibration, especially harmonic motion, is an important part of the physical competition, and it is also a place where students feel more difficult. This article tries to sum up this conclusion. If the object is a simple harmonic motion, the restoring force F and the displacement x relative to the equilibrium position satisfy the following relationship, ie, F=-kx. Theoretically, it can be proved that the solution of this differential equation of motion is x=Acos(ωt+φ0), ω is the circular frequency of the vibrating object, which is determined by the nature of the system itself, ie