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首先根据表1,表11求总平方和:校正项C·T=T~2/(1abr)=((4603.3)~2)/(2×4×5×3)=176586.42, 总S·S=∑x~2-C·T=19.7~2+28.6~2+20.3~2+……+24.6~2+22.7~2+45.5~2+47.5~2+54.2~2+……
First of all, based on Table 1 and Table 11, find the sum of squares: Correction term C · T = T ~ 2 / (1abr) = ((4603.3) ~ 2) / (2 × 4 × 5 × 3) = 176586.42, total S · S = Σx ~ 2-C · T = 19.7~2 + 28.6~2 + 20.3~2 + ... + 24.6~2 +22.7~2 +45.5~2 +47.5~2 +54.2~2 + ...