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例1计算:(3~(1/2)+1)~(2005)-2(3~(1/2)+1)~(2004)- 2(3~(1/2)+1)~(2003)+2005.分析式子前三项有公因式(3~(1/2)+1)~(2003),将其提出来,此题便可以轻而易举地解决了.
Example 1 Calculation: (3~(1/2)+1)~(2005)-2(3~(1/2)+1)~(2004)- 2(3~(1/2)+1)~ (2003)+2005. The first three terms of the analysis formula have a common factor (3~(1/2)+1)~(2003), which can be solved easily.