在一篇文章中见到这样的看法:“函数y=f(x)的图象和它的反函数y=f~(-1)(x)的图象关于直线y=x对称,则它们的交点(如果相交)在直线y=x上。因此求交点,即解方程组等价于解方程f(x)=f~(-1)(x),又等价于解方程f(x)=x(或f~(-1)(x)=x)。”用以下结论解题笔者认为,这种看法不妥,还应商榷。 In an article, we see this: “The image of the function y=f(x) and its image of the inverse function y=f~(-1)(x) are symmetrical about the straight line y=x, then they The point of intersection (if intersecting) is on the straight line y=x, so the intersection point is solved, ie, the solution equation is equivalent to the solution equation f(x)=f~(-1)(x), which is equivalent to the solution equation f(x). ) = x (or f ~ (-1) (x) = x)." Solve the problem with the following conclusion: I think this view is not correct, we must discuss.