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众所周知,在△ABC中,有不等式: ctgA/2·ctgB/2+ctgB/2·ctgC/2+ctgC/2·ctgA/2≥9 (1) 本文旨在向读者介绍(1)式的一种巧妙证法。
As we all know, in △ABC, there is an inequality: ctgA/2.ctgB/2+ctgB/2.ctgC/2+ctgC/2.ctgA/2≥9 (1) This article aims to introduce the reader to the (1) formula. Kind of ingenious proof.