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1.数据与目标函数在本文的論述过程中,下列数据是已知的: 1.調度站A到各装卸线A_i(i=1,2’…,n)的运行往返时间、捣车作业时間及装卸作业时间等的时間和t_i>)(i=1,2,…,n)。 2.A站向各线A_i取送車輛的車数C_i>)(i=1,2,…,n)。为了方便,我們假定只有一台机車在作业,并设机车按下列順序取送車輛,那么当机車給A_l綫取送时,剩下的(n-1)个綫的車輛每輛应等待t_l时分之后才有可能被取送;而当机車依次給A_j线取送車輛时,其余(n-2)个綫的車輛每輛应增加等待时间t_j时分,即等待(t_i+t_j)时分后才有可能被取送;依此类推,最后一綫的車輛每辆应等侍(t_l+t_j+t_k+…+t_q)时分后才能被取送。因此,依上述任意順序取送車輛必然造成車輛停
1. Data and Objective Functions In the process of this article, the following data is known: 1. Runtime of dispatch station A to each loading and unloading line A_i (i=1, 2’..., n) Time and t_i>) (i=1, 2, ..., n). 2. A station fetches the number of vehicles C_i>) (i=1, 2,..., N) to each line A_i. For the sake of convenience, we assume that only one locomotive is in operation and the locomotive is set to pick up the vehicles in the following order. When the locomotive picks up the A_l line, the remaining (n-1) lines of vehicles should each wait. T_l may be fetched after the hour; when the locomotive in turn routes the vehicle to the A_j line, the remaining (n-2) lines of the vehicle shall each increase the waiting time t_j, ie wait (t_i+t_j) It is only then that it can be fetched; by analogy, each vehicle in the last line should wait until (t_l+t_j+t_k+...+t_q) to be sent. Therefore, taking the vehicle in any order above will inevitably cause the vehicle to stop