模型如图1,2,求点A到圆上各点的最大距离与最小距离.如图1,点A到⊙O的最大距离为AC,最小距离为AB.如图2,点A到⊙O的最大距离为AC,最小距离为AB.证明在⊙O上任取点D,连接AD,OD.由三角形两边之差小于第三边,两边之和大于第三边,同圆中半径都相等,可知图1中, As shown in Figure 1 and Figure 2, the maximum distance and the minimum distance of each point from point A to the circle are shown in Figure 1. As shown in Figure 1, the maximum distance from point A to ⊙O is AC and the minimum distance is AB. O is the maximum distance of AC, the minimum distance of AB. Prove that any point in the ⊙O D, connecting AD, OD. Triangle by the difference between the two sides is less than the third side, both sides of the sum of the third side, with the same radius of the circle , We can see in Figure 1,