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一、化学因数和因数法计算 [例1]1.3克锌跟足量的盐酸反应,能产生多少克氢气? 解:设能产生x克氢气Zn+2HCl=ZnCl_2+H_2↑65 21.3克 x克列比例式 65:2=1.3:xX=(2×1.3)/65=0.04(克)把上式作一下数学处理,也可以写成x=1.3×2/65=0.04(克)即产生氢气的质量=参加化学反应的锌的质量(克)×化学方程式中表示的氢气的量/化学方程式中表示的锌的量
First, the calculation of chemical factor and factor method [Example 1] 1.3 grams of zinc with sufficient amount of hydrochloric acid reaction, how many grams of hydrogen gas can produce? Solution: set to produce x grams of hydrogen Zn + 2HCl = ZnCl 2 + H_2 ↑ 65 21.3 g x gram The ratio formula 65:2=1.3:xX=(2*1.3)/65=0.04 (g) treats the above equation as a mathematical process, and can also be written as x=1.3×2/65=0.04 (grams), ie, the quality of the hydrogen produced. = mass of zinc participating in the chemical reaction (g) × amount of hydrogen expressed in the chemical equation / amount of zinc expressed in the chemical equation