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☆基础篇 课时一不等式的性质 诊断检测 一、填空题 1.设a=2x2+x-1,b=3x2-x,则a,b的大小关系为_. 2.若0<α<π/3<β<π/2,则α-β的取值范围是_. 3.已知-1b,则 a2>b2;②若a2>b2,则|a|>b;③若a>|b|,则a2>b2;④若a2>b2,则a>|b|.
☆ Fundamental lesson time Inequality The nature of the diagnosis test 1. Fill in the blank question 1. Let a=2x2+x-1, b=3x2-x, then the relationship between a and b is _. 2. If 0<α<π/ 3<β<π/2, then the range of α-β is _. 3. Known that -1b, then a2>b2; 2 if a2>b2, then |a|>b;3 if a>| b|, then a2>b2; 4 if a2>b2, then a>|b|.