题1已知p:|2x-3|1,q:1x2+x-60,则p是q的().(A)充分不必要条件(B)必要不充分条件(C)充要条件(D)既不充分也不必要条件解∵p:|2x-3|1x2或x1,∴p:1≤x≤2,∵q:1x2+x-60x2或x-3,∴q:-3≤x≤2,故p是q的充分而不必要条件.选(A).解答错了!错在哪里?因为讨论q与q,应该首先考虑 Problem 1 is known as p:|2x-3|1, q: 1x2+x-60, then p is q (). (A) sufficient unnecessary condition (B) necessary insufficient condition (C) necessary and sufficient condition ( D) neither sufficient nor necessary conditional solution p:|2x-3|1x2 or x1, ∴p: 1≤x≤2, ∵q: 1x2+x-60x2 or x-3, ∴q: -3≤ x ≤ 2, so p is a sufficient and unnecessary condition of q. (A). The solution is wrong! Where is the error? Because q and q should be considered, we should first consider