题设a,b∈R+,且a+b=1,λ0是方程(2x-1)(x-1)-2=0的一个解,且λ0∈(1,2),证明或否定,当λ≥λ0时,1aλ+1+1bλ+1≤2λ+12λ+1,等号当且仅当a=b=12时成立.(注命题人为第一位解答正确者提供奖金50元.)有奖解题擂台(75)@郭要红$安徽师范大学数学系!邮编:241000 Let a, b∈R+, and a+b=1, λ0 is a solution to the equation (2x-1)(x-1)-2=0, and λ0∈(1,2), proved or negated when When λ≥λ0, 1aλ+1+1bλ+1≤2λ+12λ+1, the equal sign holds if and only if a=b=12. Prize-solving Titles (75) @ Guo Yaohong (Department of Mathematics, Anhui Normal University) : 241000