我们知道,若OA(向量)+OB(向量)=0,则OA(向量)与OB(向量)互为相反向量.从形上考虑,O是线段AB的中点,线段OA与OB长度相等.这是一维的情形.已知ABC,若OA(向量)+OB(向量)+OC(向量)=0,则O是ABC的重心,且S_(△OAB)=S_(△OBC)=S_(△OCA).这是二维的情形.运用类比联想,对于三维的情形有如下猜想:猜想1已知四面体ABCD, We know that OA (vector) and OB (vector) are opposite vectors when OA (vector) + OB (vector) = 0. From a metaphorical point of view, O is the midpoint of segment AB and segment OA is equal to the length of OB This is a one-dimensional case. It is known that OABC is the center of gravity of ABC if OA (vector) + OB (vector) + OC (vector) = 0 and S_ (Δ OAB) = S_ ) = S_ (OCA) .This is a two-dimensional situation.Using analogy association, for the three-dimensional case has the following conjecture: Conjecture 1 Known tetrahedron ABCD,