不等式恒成立问题是函数与不等式综合问题的重要内容,体现了导数工具性的重要应用,是历年各省市高考命题的常见题型,问题求解的通法是构造函数,将问题转化为求函数的最值。1直接构造法例1已知f(x)=a(x-lnx)+(2x-1)/x~2,a∈R。(Ⅰ)讨论f(x)的单调性;(Ⅱ)当a=1时,证明f(x)>f′(x)+3/2对于任 Inequality constant problem of establishment is an important part of the comprehensive function and inequality problem, which reflects the important application of the derivative tool, which is the common type of college entrance examination propositions over the years. The common problem solving method is the constructor, which transforms the problem into the function The most value. 1 Direct Structure Law 1 is known f (x) = a (x-lnx) + (2x-1) / x ~ 2, a∈R. (Ⅰ) discuss the monotonicity of f (x); (Ⅱ) when a = 1, we prove that f (x)> f ’