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采用溶剂热法,在乙醇和乙二醇的混合溶剂中,p H=8.5条件,150℃,反应12h,一步合成了LaPO4:Eu3+晶体.室温下,用X射线衍射对材料的组成进行了表征,XRD数据表明,成功合成了LaPO4:Eu3+晶体.荧光光谱分析表明,在352nm紫外光激发下,其发射峰在531nm、640nm,分别对应着Eu3+的5D0→7F0和5D0→7F3能级跃迁.并讨论了离子La3+∶Eu3+不同浓度掺杂比对荧光性质的影响,结果表明,Eu3+的最佳掺杂浓度比为10%.
The crystal structure of LaPO4: Eu3 + was synthesized in one step by solvothermal method under the condition of p H = 8.5 in a mixed solvent of ethanol and ethylene glycol and reaction at 150 ℃ for 12 h. The composition of the material was characterized by X-ray diffraction The results of XRD show that LaPO4: Eu3 + crystal was synthesized successfully, and the fluorescence spectra showed that the emission peaks of LaPO4: Eu3 + were at 531nm and 640nm, respectively, corresponding to the 5D0 → 7F0 and 5D0 → 7F3 transitions of Eu3 + The effects of La3 +: Eu3 + doping ratio on the fluorescence properties were discussed. The results show that the optimum doping concentration of Eu3 + is 10%.