文[1]证明了文[2]中关于纯循环小数的一个猜想是正确的,笔者最近又发现了该猜想还可推广.定理1若(q,10)=1,q≥3,则1q可化为纯循环小数,且其循环节长度可为任意正整数s的倍数ms(m,s∈N*),即可设1q=0.a1a2…ams(又记a1a2…ams=b1,b2,…,bm,其中b1=a1a2…as,b2=as+1as+2…a2s, The paper [1] proved that the conjecture of the pure loop decimal in [2] is correct. The author has recently found that the conjecture can be extended. Theorem 1 If (q, 10) = 1, q ≥ 3, then 1q Can be converted into a pure loop decimal, and the length of the loop section can be any multiple of a positive integer s ms (m, s ∈ N *), can be set 1q = 0. a  1a2 ... a  ms (also remember a1a2 ... ams =b1,b2,...,bm, where b1=a1a2...as,b2=as+1as+2...a2s,