定点问题是高中数学的一个重点,也是一个难点．许多同学一遇到这类问题就头疼,不知该从何下手．下面我给大家提供一种思路清晰、有章可循、操作性强的方法——分离参数法．例1已知2a-3b=1,证明直线ax+by =5恒过定点．证明∵2a-3b=1,∴a=1/2(3b+1)．代入直线方程后分离出参数b得(x-10)+b(3x+2y)=0①∵b可取任意实数,∴①式成立须满足解得∴方程(x-10)+b(3x+2y)=0表示经 The fixed point problem is a key point in high school mathematics, and it is also a difficult point. Many classmates have headaches when they encounter such problems. I do not know where to start. Here I will provide you with a clear-cut, rule-based, and practical approach - the separation of parameters. Example 1 knows that 2a-3b=1, proves that the straight line ax+by = 5 is constant over fixed point. Prove that ∵2a-3b=1, ∴a=1/2(3b+1). Substituting the linear equation into the parameter b (x-10)+b(3x+2y)=01∵b can take any real number, and formula 成立1 must be satisfied to solve the equation (x-10)+b(3x+2y). ) = 0 means that