【摘 要】
：
采用Boltzmann-Langevin方程研究了能量为35MeV／u的14Be,8He,6He,11Li,17B,11Be,19C与 12C靶的反应,计算了产生中子集团的截面,发现14Be与12C靶反应产生4n的截面与实验值符合
【机 构】
：
兰州重离子加速器国家实验室原子核理论中心,兰州重离子加速器国家实验室原子核理论中心,兰州重离子加速器国家实验室原子核理论中心 兰州 730000 中国科学院近代物理研究所 兰州 730000 中国科学
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采用Boltzmann-Langevin方程研究了能量为35MeV／u的14Be,8He,6He,11Li,17B,11Be,19C与 12C靶的反应,计算了产生中子集团的截面,发现14Be与12C靶反应产生4n的截面与实验值符合得很好．通过这几个入射核与12C靶形成中子集团截面的对比,发现核的晕中子越多产生中子集团的截面越大,晕中子数相同时,质量数越大产生中子集团的截面越大．中子集团可能主要来自晕核子．
The reactions of 14Be, 8He, 6He, 11Li, 17B, 11Be, 19C and 12C with energy of 35MeV / u were studied by using the Boltzmann-Langevin equation. The cross section of the neutron group was calculated. It was found that the reaction of 14Be with 12C produced 4n Cross-section and experimental values in good agreement. By comparing the cross sections of neutron groups formed by these incident nuclei and 12C target, it is found that the larger the halo neutron of the nucleus is, the larger the cross section of the neutron group is generated and the same is the number of halo neutrons. The larger the mass number is, the larger the neutron group The larger the cross section The neutron group may come mainly from halo nuclei.
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