在全国各地中考中,图形最值问题的考查一直是热点问题,此类问题有两个大解题模型,举例说明如下.一、构建函数关系求解例1(2015·江苏泰州)如图1,正方形ABCD的边长为8cm,E、F、G、H分别是AB、BC、CD、DA上的动点,且AE=BF=CG=DH.求四边形EFGH面积的最小值.解析此题易证,△AEH≌△BFE≌△CGF≌△DHG,设四边形EFGH面积为S,设BE=xcm,则BF=(8-x)cm, In the mid-school exams throughout the country, the examination of the most profiling of graphs has always been a hot issue, and there are two major problem solving models for such problems, as follows: First, construct function relation solving example 1 (2015 · Taizhou, Jiangsu) The side length of square ABCD is 8cm, E, F, G and H are the moving points on AB, BC, CD and DA respectively, and AE = BF = CG = DH. Find the minimum area of ​​quadrilateral EFGH. The formula, △ AEH △ △ BFE △ △ CGF △ DHG, set the quadrilateral EFGH area S, set BE = xcm, then BF = (8-x) cm,