题已知a是实数,函数f(x)=2ax2+2x-3-a.如果函数y=f(x)在区间[-1,1]上有零点,求a的取值范围.这是2007年广东高考试题文科压轴题、理科第20题.许多书刊给出命题组的两种标准答案,但解法都很繁琐,这里给出一个相对简单的解法供大家参考.解当a=0时,函数f(x)=2x-3在区间[-1,1]上没有 Given that a is a real number, the function f (x) = 2ax2 + 2x-3-a. Find the range of a if the function y = f (x) has zeros in the interval [-1,1] 2007 Guangdong college entrance examination subjects of science finale, Science Question 20. Many books give two standard answers to the proposition group, but the solution is very complicated, here is a relatively simple solution for your reference. Solution when a = 0 , The function f (x) = 2x-3 does not exist in the interval [-1,1]