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高中教材《化学平衡》一节中有这样两段不一致的文字表述:“在500℃、压强为1.01×10~5帕斯卡时,如果把2体积的SO_2和1体积的O_2的混和物,通入一个装有催化剂的密闭容器里,结果能得到含91%(体积组成)SO_3的混和气体。这时候,容器里的反应物SO_2、O_2和生成的SO_3在混和物中的浓度就不再变化”。“如果不是从SO_2和O_2的混和物开始反应,而是使纯净的SO_3,在同样的温度(500℃)、压强(1.01×10~5帕斯卡)和催化剂存在的条件下起反应,SO_3分解为SO_2和O_2,当达到平衡状态时,混和气体仍然含有91%(体积)的SO_3。”
There are two inconsistent written expressions in the high school textbook “Chemical Equilibrium”: “If the pressure is 1.01×10-5 Pascals at 500°C, if you mix 2 volumes of SO 2 and 1 volume of O 2 , In a closed container with a catalyst, a mixed gas containing 91% by volume of SO 3 can be obtained. At this time, the concentrations of the reactants SO 2 , O 2 and produced SO 3 in the container no longer change in the mixture. . “If the reaction is not started from the mixture of SO 2 and O 2 , but pure SO 3 is reacted at the same temperature (500° C.), pressure (1.01×10 −5 Pascals) and the presence of a catalyst, SO 3 is decomposed into SO 2 and O 2 , when the equilibrium state is reached, the mixed gas still contains 91% by volume of SO 3 ."