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m+n与m-n称为对偶式.本文用对偶式解三道根式问题.例1设(?),求(?)的值.解由(?)知道(?),则xy=1,x-y=1.于是原式(?)例2已知x=1/2(19911/n-19911/n)(n是自然数)
m+n and mn are called duality. This paper uses a dual solution to the triple root problem. Example 1 Let (?) find the value of (?). The solution is known by (?), then xy=1, xy = 1. Then the original (?) Example 2 is known x = 1/2 (19911/n-19911/n) (n is a natural number)