论文部分内容阅读
如附图所示。今有由活塞固定的 A、B 容器(截面积相等),分别向其中充入理想气体。两侧的活塞中间用杆连接。当 A 容器内的体积为 B 容器内体积的1.8倍时,即处于平衡状态。当连杆上加力 F(如附图)时,则两侧的气体体积相等。如果将此力改为反方向时,那么 A、B 的体积之比是多少?(设气体的温度保持不变)解:设最初在容器 A、B 内的气体的压强均为 p,如果 B 的体积为 V 时,则 A 的体积为1.8V。如果在连接棒上加上
As shown in the figure. There are A and B containers fixed by the piston (the cross-sectional area is equal), and the ideal gas is filled into them. The pistons on both sides are connected by rods. When the volume in the A container is 1.8 times the volume of the B container, it is in equilibrium. When force F on the connecting rod (as in the drawing), the gas volume on both sides is equal. If this force is changed to the opposite direction, what is the ratio of the volumes of A and B? (Assuming the temperature of the gas remains unchanged) Solution: Let the pressure of the gas in the first container A, B be p, if B When the volume is V, the volume of A is 1.8V. If you add on the connecting rod