只用折纸的方法,能不能找出正方形一条边的三等分、五等分、七等分等等的奇数等分点呢?1.折纸方法.如图1,先将正方形左右对折,再对折,再对折,折痕交AB于点E_1、E_2、E_3、E_4、E_5、E_6、E_7.将纸片展开,把纸片的左下角折叠,使点D与点E_n(n=1,2,3,4,5,6,7)重合,点C落在点P处,折痕MN分别交AD、BC于点M、N,PE_n交BC于点Q.则点Q就是有关的等分点.2.证明.设正方形ABCD边长为1,ME_n=x,则 Only the origami method, can you find out one side of the square of the third, fifth, seventh and so on the odd equal points? 1. Origami method. As shown in Figure 1, the first square about folded, then Fold, then fold, crease cross AB points E_1, E_2, E_3, E_4, E_5, E_6, E_7. Expand the paper, the lower left corner of the paper folded, so that point D and point E_n (n = 1,2 , 3, 4, 5, 6, 7) coincide, point C falls at point P, crease MN respectively pay AD, BC at point M, N, PE_n to pay BC at point Q. Then point Q is the relevant point Point .2. Proof. Set the square ABCD side length of 1, ME_n = x, then